document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106224>Question 106224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried to solve this using several equations, none seem to work.  The one that I think came the closest was (this did not come from a math textbook, it came from an online assignment for intermediate algebra):\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=200%2Fx=200%2F%28x%2B10%29%2B1 ALIGN=MIDDLE  ALT=\"200%2Fx=200%2F%28x%2B10%29%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "when I solved it I got x = -50 and x = 40\r<BR>\n" );
document.write( "\n" );
document.write( "Here is the word problem:\r<BR>\n" );
document.write( "\n" );
document.write( "Steve traveled 200 miles at a certain speed.  Had he gone 10 mph faster, the trip would have taken 1 hour less.  Find the speed of his vehicle.\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks for your help!!\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77270 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=st d=distance, s=speed, t=time<BR>\n" );
document.write( "d=200 miles, s=Steve's speed in mph, t= his time in hrs<BR>\n" );
document.write( "The distance of both trips is the same. So,:<BR>\n" );
document.write( "st=200<BR>\n" );
document.write( "t=200/s<BR>\n" );
document.write( "(s+10)(t-1)=200<BR>\n" );
document.write( "st+10t-s-10=200<BR>\n" );
document.write( "s*200/s+10*200/s-s-10=200 plug 200/s for every t in the above equation.<BR>\n" );
document.write( "200+2000/s-s-10=200<BR>\n" );
document.write( "2000/s-s-10=0<BR>\n" );
document.write( "-s^2-10s+2000=0 multiply both sides by s to eliminate the fraction.<BR>\n" );
document.write( "s^2+10s-2000=0 multiply both sides times -1<BR>\n" );
document.write( "(s+50)(s-40)=0<BR>\n" );
document.write( "s can't be a negative number.<BR>\n" );
document.write( "s=40 mph<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "at 40 mph it takes 5 hrs to go 200 mi<BR>\n" );
document.write( "at 50 mph it takes 1 hr less<BR>\n" );
document.write( "you had the right answer all the time and didn't know it!<BR>\n" );
document.write( "Ed\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );