document.write( "Question 1151062: Log8x+log4(1/6)=1/3 \n" ); document.write( "
Algebra.Com's Answer #772685 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "\"log%288%2Cx%29%2Blog%284%2C%281%2F6%29%29+=+1%2F3\"

\n" ); document.write( "Convert the log base 8 and the log base 4 to logs base 2:

\n" ); document.write( "\"%281%2F3%29log%282%2Cx%29%2B%281%2F2%29log%282%2C%281%2F6%29%29=+1%2F3\"

\n" ); document.write( "Convert the expression on the left to a single log base 2 using rules of logarithms:

\n" ); document.write( "\"log%282%2C%28%28x%5E%281%2F3%29%2A%281%2F6%29%5E%281%2F2%29%29%29%29+=+1%2F3\"

\n" ); document.write( "Convert the logarithmic equation to exponential form:

\n" ); document.write( "\"x%5E%281%2F3%29%2A%281%2Fsqrt%286%29%29+=+2%5E%281%2F3%29\"

\n" ); document.write( "Isolate the term with the variable:

\n" ); document.write( "\"x%5E%281%2F3%29+=+2%5E%281%2F3%29%2Asqrt%286%29\"

\n" ); document.write( "Cube both sides of the equation:

\n" ); document.write( "\"x+=+2%2A%286%2Asqrt%286%29%29\"
\n" ); document.write( "\"x+=+12%2Asqrt%286%29\"

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