document.write( "Question 1151038: A family's vacation destination is 850 miles from their home. They travel by car 6 hours on the first day of their trip. Their average speed is 45 mph. The next day they travel 7 hours, averaging the same speed. How many miles are left for the family to travel?\r
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Algebra.Com's Answer #772630 by MathLover1(20850)\"\" \"About 
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A family's vacation destination is \"850\" miles from their home.
\n" ); document.write( "\"d=800mil\"\r
\n" ); document.write( "\n" ); document.write( "They travel by car \"t%5B1%5D=6h\"on the first day of their trip. Their average speed is \"s%5B1%5D=45%28mil%2Fh%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d%5B1%5D=s%5B1%5D%2At%5B1%5D\"
\n" ); document.write( "\"d%5B1%5D=45%28mil%2Fh%29%2A6h\"
\n" ); document.write( "\"d%5B1%5D=45%28mil%2Fcross%28h%29%29%2A6cross%28h%29\"
\n" ); document.write( "\"d%5B1%5D=45mil%2A6\"
\n" ); document.write( "\"d%5B1%5D=270mil\"->the first day of their trip\r
\n" ); document.write( "\n" ); document.write( " The next day they travel \"t%5B2%5D=7h\", averaging the \"same\" speed. \r
\n" ); document.write( "\n" ); document.write( "\"d%5B2%5D=s%5B2%5D%2At%5B2%5D\"
\n" ); document.write( "\"d%5B2%5D=45%28mil%2Fh%29%2A7h\"
\n" ); document.write( "\"d%5B2%5D=45%28mil%2Fcross%28h%29%29%2A7cross%28h%29\"
\n" ); document.write( "\"d%5B2%5D=45mil%2A7\"
\n" ); document.write( "\"d%5B2%5D=315mil\"->the second day of their trip\r
\n" ); document.write( "\n" ); document.write( "How many miles are left for the family to travel?\r
\n" ); document.write( "\n" ); document.write( " in two days they have traveled: \"d%5B1%5D%2Bd%5B2%5D=270mil%2B315mil=585mil\"\r
\n" ); document.write( "\n" ); document.write( "\"d-%28d%5B1%5D%2Bd%5B2%5D%29=800mil-585mil=215mil\"\r
\n" ); document.write( "\n" ); document.write( "answer: \"215mil\" are left for the family to travel\r
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