document.write( "Question 1150998: Bruslan is the architect in charge of designing a new elementary school. He has been told that each rectangular classroom should include 25m^2 of common space, plus 1.50m^2 per students for desks and chairs. If the maximum number of students in the class is 22, what is the least possible perimeter that the classroom design could have? \n" ); document.write( "
Algebra.Com's Answer #772626 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "            The correct solution is below.\r
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document.write( "You determine first the area of the class room for 22 students\r\n" );
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document.write( "    Area = 25 + 22*1.5 = 58 square meters.\r\n" );
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document.write( "A rectangle which provides the minimum perimeter at given area, is THE SQUARE with the side length equal to square root of the area.\r\n" );
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document.write( "In this case, the classroom with minimal perimeter is the square with the side length of\r\n" );
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document.write( "    \"sqrt%2858%29\" = 7.616 meters.    \r\n" );
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document.write( "The least possible perimeter is then  4*7.616 = 30.464 meters (approximately).       ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "If you want to see many other similar optimization problems,  look into my lesson\r
\n" ); document.write( "\n" ); document.write( "    - Calculus optimization problems\r
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\n" ); document.write( "\n" ); document.write( "Specifically,  for the given problem,  its precise analogue is the  Problem 3  of the referred lesson.\r
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