document.write( "Question 1151033: Sam invested $ 1750, part of it at 6% and the rest at 8% yearly interest. The yearly income on the 8% investment was $30 more than twice the income from the 6% investment . How much did he invest at each rate \n" ); document.write( "

Algebra.Com's Answer #772623 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = amount invested @ 6%
\n" ); document.write( " $\"+1750+-+x+\"$ = amount invested @ 8%
\n" ); document.write( "---------------------------------------------------
\n" ); document.write( " $\"+.08%2A%28+1750+-+x+%29+=+2%2A.06x+%2B+30+\"$
\n" ); document.write( " $\"+140+-+.08x+=+.12x+%2B+30+\"$
\n" ); document.write( " $\"+.2x+=+110+\"$
\n" ); document.write( " $\"+x+=+550+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+1750+-+x+=+1200+\"$
\n" ); document.write( "----------------------------
\n" ); document.write( "$550 invested @ 6%
\n" ); document.write( "$1,750 invested @ 8%\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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