document.write( "Question 1151018: Subtract 13-32 Mod 3. Please Full Working \n" ); document.write( "

Algebra.Com's Answer #772596 by ikleyn(52817) $\"\"$ $\"About$

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document.write( "    13 (mod 3)  is the remainder of division of the number 13 by 3.\r\n" );
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document.write( "    So,  13 (mod 3) is 1   (13 = 4*3 + 1, therefore, 13 (mod 3) = 1 (mod 3) ).\r\n" );
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document.write( "    32 (mod 3) is the remainder of division of the number 32 by 3.\r\n" );
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document.write( "    So,  32 (mod 3) is 2   (32 = 10*3 + 2, therefore, 32 (mod 3) = 2 (mod 3) ).\r\n" );
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document.write( "    Therefore,  13 - 32 (mod 3)  = 1 - 2 (mod 3) = -1 (mod 3) = 2 (mod 3).  \r\n" );
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document.write( "     ANSWER.  13 - 32 (mod 3) = 2 (mod 3).\r\n" );
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