document.write( "Question 1150954: five years ago Jacob was one sixth of the age of his brother. In three years time his ager doubled will match his brother age. How old is Jacob now? \n" ); document.write( "
Algebra.Com's Answer #772528 by ankor@dixie-net.com(22740)\"\" \"About 
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Let j = Jacob's present age
\n" ); document.write( "let b = brother's \" \"
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( " five years ago Jacob was one sixth of the age of his brother.
\n" ); document.write( "j - 5 = \"1%2F6\"(b-5)
\n" ); document.write( "j = \"1%2F6\"(b-5) + 5
\n" ); document.write( "multiply by 6 to get rid of the fraction
\n" ); document.write( "6j = b - 5 + 30
\n" ); document.write( "6j = b + 25
\n" ); document.write( "or we could write
\n" ); document.write( "b = 6j - 25
\n" ); document.write( " In three years time, his age doubled, will match his brother age.
\n" ); document.write( "b + 3 = 2(j+3)
\n" ); document.write( "b + 3 = 2j + 6
\n" ); document.write( "b = 2j + 6 - 3
\n" ); document.write( "b = 2j + 3
\n" ); document.write( "replace b with (6j-25)
\n" ); document.write( "6j - 25 = 2j + 3
\n" ); document.write( "6j - 2j = 3 + 25
\n" ); document.write( "4j = 28
\n" ); document.write( "j = 28/4
\n" ); document.write( "j = 7 yrs is Jacob's present age
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\n" ); document.write( "Check this, find b
\n" ); document.write( "b = 2(7) + 3
\n" ); document.write( "b = 17
\n" ); document.write( "Check in the statement
\n" ); document.write( "\" In three years time his age doubled will match his brother age.
\n" ); document.write( "2(7+3) = 17 + 3
\n" ); document.write( "2(10) = 20
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