document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104264>Question 104264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is two more than a second number. twice the first number is 4 less than 3 times the second. find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77251 by </B><A HREF=/tutors/aboutme.mpl?userid=BurningFlame_marc><B>BurningFlame_marc(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BurningFlame_marc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=BurningFlame_marc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello!\r<BR>\n" );
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document.write( "This is how I solve this kind of problems.\r<BR>\n" );
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document.write( "Representations: x=1st number, x-2=2nd number.<BR>\n" );
document.write( "Equation:2x=3(x-2)-4<BR>\n" );
document.write( "Solution:<BR>\n" );
document.write( "2x=3(x-2)-4<BR>\n" );
document.write( "2x=3x-6-4<BR>\n" );
document.write( "2x=3x-10<BR>\n" );
document.write( "-x=-10<BR>\n" );
document.write( "x=10<BR>\n" );
document.write( "x-2=8\r<BR>\n" );
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document.write( "Final Answer: the 1st number is 10 and the 2nd number is 8. </SPAN>\n" );
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