document.write( "Question 1150878: A piggy bank contains only quarters and nickels, and there is a total of 60 coins. The total value of the coins is $7.40, so how many coins are there? \n" ); document.write( "
Algebra.Com's Answer #772432 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "let quarters be \"q\" and nickels \"n\"
\n" ); document.write( "value of the coins is: \"q\"=$\"0.25\" and \"n\"=$\"0.05\"\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( " there is a total of \"60\" coins, so\r
\n" ); document.write( "\n" ); document.write( "\"q%2Bn=60\" \r
\n" ); document.write( "\n" ); document.write( "\"q=60-n\" ...........eq.1\r
\n" ); document.write( "\n" ); document.write( "The total value of the coins is $\"7.40\", so \r
\n" ); document.write( "\n" ); document.write( "\"0.25q%2B0.05n=7.40\" .......substitute \"q\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"0.25%2860-n%29%2B0.05n=7.40\".........solve for \"n\"\r
\n" ); document.write( "\n" ); document.write( "\"15-0.25n%2B0.05n=7.40\"\r
\n" ); document.write( "\n" ); document.write( "\"15-0.20n=7.40\"\r
\n" ); document.write( "\n" ); document.write( "\"15-7.40=+0.20n\"\r
\n" ); document.write( "\n" ); document.write( "\"7.60=+0.20n\"\r
\n" ); document.write( "\n" ); document.write( "\"n=7.60%2F+0.20\"\r
\n" ); document.write( "\n" ); document.write( "\"n=38\"\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"q=60-n\" ...........eq.1\r
\n" ); document.write( "\n" ); document.write( "\"q=60-38\" \r
\n" ); document.write( "\n" ); document.write( "\"q=22\" \r
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\n" ); document.write( "\n" ); document.write( "so, there are \"22\" quarters and \"38\" nickels\r
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\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"0.25q%2B0.05n=7.40\"\r
\n" ); document.write( "\n" ); document.write( "\"0.25%2A22%2B0.05%2A38=7.40\"\r
\n" ); document.write( "\n" ); document.write( "\"5.50%2B1.90=7.40\"\r
\n" ); document.write( "\n" ); document.write( "\"7.40=7.40\"\r
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