document.write( "Question 1150855: Samples of size n = 240 are randomly selected from the population of numbers (0 through 20) produced by a random-number generator, and the variance is found for each sample. What is the distribution of the sample variances?\r
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\n" ); document.write( "\n" ); document.write( "A)skewed to the left\r
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\n" ); document.write( "\n" ); document.write( "B)normal (approximately)\r
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\n" ); document.write( "\n" ); document.write( "C)skewed to the right\r
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\n" ); document.write( "\n" ); document.write( "D)not enough information provided
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Algebra.Com's Answer #772429 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The sample size n = 240 satisfies the inequality n > 30. \r
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\n" ); document.write( "\n" ); document.write( "So the distribution of sample variances will be approximately normal according to the Central Limit Theorem (CLT). This theorem says that whenever n > 30, then the distribution of sample means, sample variances, etc will be approximately normal. This is handy when doing things like finding areas under the curve to determine P values.\r
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\n" ); document.write( "\n" ); document.write( "Answer: B) normal (approximately)\r
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\n" ); document.write( "\n" ); document.write( "side note: I honestly don't know what the tutor @MathLover1 is referring to when they wrote \"would have to make it a good 80 by 90 by 80 by 90 by 80 which would be 4+4 and make that 69\". It's possible they mixed up two problems together.
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