document.write( "Question 1150869: Hi\r
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\n" ); document.write( "\n" ); document.write( "4 to the power of x plus 6 to the power of x equals 9 to the power of x. \r
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Algebra.Com's Answer #772417 by ikleyn(52777)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The given exponential equation\r\n" );
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document.write( "    \"4%5Ex\" + \"6%5Ex\" = \"9%5Ex\"             (1)\r\n" );
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document.write( "is equivalent to\r\n" );
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document.write( "    \"2%5E%282x%29\" + \"6%5Ex%29\" = \"3%5E%282x%29\",   or\r\n" );
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document.write( "    \"2%5E%282x%29\" + \"2%5Ex%2A3%5Ex\" = \"3%5E%282x%29\".          (2) \r\n" );
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document.write( "Introduce new variables  u = 2^x,  v = 3^x.  Then equation (2) takes the form\r\n" );
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document.write( "    u^2 + u*v = \"v%5E2\".\r\n" );
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document.write( "Divide both sides by u^2.  You will get\r\n" );
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document.write( "    \"%28v%2Fu%29%5E2\" - \"v%2Fu\" - 1 = 0                (3)\r\n" );
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document.write( "Let z = \"v%2Fu\".   Then equation (3) takes the form\r\n" );
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document.write( "    z^2 - z - 1 = 0.\r\n" );
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document.write( "Solve this quadratic equation using the quadratic formula\r\n" );
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document.write( "    \"z%5B1%2C2%5D\" = \"%281+%2B-+sqrt%28%28-1%29%5E2+%2B+4%29%29%2F2\" = \"%281+%2B-+sqrt%285%29%29%2F2\".\r\n" );
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document.write( "The roots are  \r\n" );
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document.write( "    \"z%5B1%5D\" = \"%281+%2B+sqrt%285%29%29%2F2\",   and\r\n" );
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document.write( "    \"z%5B2%5D\" = \"%281+-+sqrt%285%29%29%2F2\".\r\n" );
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document.write( "Thus, we should consider two cases.\r\n" );
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document.write( "(a)  \"z%5B1%5D\" = \"%281%2Bsqrt%285%29%29%2F2%29\".\r\n" );
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document.write( "     It means  \"%281%2Bsqrt%285%29%29%2F2%29\" = \"v%2Fu\" = \"%283%2F2%29%5Ex\".\r\n" );
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document.write( "     Next, take any logarithm, log base 10, or natural logarithm \"ln\"  from both sides to continue\r\n" );
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document.write( "       \"log%2810%2C+%28%281%2Bsqrt%285%29%29%2F2%29%29\" = \"x%2A%28log%2810%2C%283%2F2%29%29%29\",\r\n" );
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document.write( "        x = \"log+%28%28%28sqrt%285%29%2B1%29%2F2%29%29\" / \"log%28%283%2F2%29%29\" =  = 1.1868  (approximately).\r\n" );
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document.write( "    Thus this case is completed.\r\n" );
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document.write( "(b)  \"z%5B2%5D\" = - \"%28sqrt%285%29%2B1%29%2F2%29\"\r\n" );
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document.write( "     It means  - \"%28sqrt%285%29%2B1%29%2F2%29\" = \"v%2Fu\" = \"%283%2F2%29%5Ex\".\r\n" );
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document.write( "     \r\n" );
document.write( "     The left side is negative, while the right side is positive.\r\n" );
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document.write( "     So, this case has no solutions.\r\n" );
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document.write( "ANSWER.  The original equation has only one root  x = \"log+%28%28%28sqrt%285%29%2B1%29%2F2%29%29\" / \"log%28%283%2F2%29%29\" =  = 1.1868  (approximately).\r\n" );
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\n" ); document.write( "\n" ); document.write( "On solving exponential equations see also the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Solving exponential equations\r
\n" ); document.write( "\n" ); document.write( "    - OVERVIEW of lessons on solving exponential equations\r
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