document.write( "Question 1150848: Solve Inequality: 2y^2 < y+1 \n" ); document.write( "
Algebra.Com's Answer #772370 by Alan3354(69443)\"\" \"About 
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Solve Inequality: 2y^2 < y+1
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\n" ); document.write( "Solve equality: 2y^2 = y+1
\n" ); document.write( "2y^2 - y - 1 = 0
\n" ); document.write( "(2y + 1)*(y - 1) = 0
\n" ); document.write( "Then change to inequality:
\n" ); document.write( "(2y + 1)*(y - 1) < 0
\n" ); document.write( "Since the product is < 0, the signs of the 2 factors must be different, one + and one negative.
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\n" ); document.write( "2y + 1 < 0 ---> y < -1/2
\n" ); document.write( "y - 1 > 0 -->=-> y > 1
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\n" ); document.write( "Or,
\n" ); document.write( "2y + 1 > 0 ---> y > -1/2
\n" ); document.write( "y - 1 < 0 --> y < 1
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\n" ); document.write( "By substitution,
\n" ); document.write( "2y + 1 < 0 ---> y < -1/2 and
\n" ); document.write( "y - 1 > 0 -->=-> y > 1 do not work.
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\n" ); document.write( "---> -1/2 < y < 1
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