document.write( "Question 1150536: 4. A manufacturer fills jars with coffee. The weight of coffee, W grams, in a jar can be modelled by a normal distribution with mean 232 grams and standard deviation 5 grams.
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document.write( "(i) Find P(W < 227)? [4 marks]
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document.write( "(ii) One hundred jars of coffee are selected at random. Find the probability that more than 23 jars contains less than 227 grams of coffee. \n" );
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Algebra.Com's Answer #772357 by Glaviolette(140)![]() ![]() You can put this solution on YOUR website! (i) z = (227-232)/5 = -1 \n" ); document.write( "P(W < 227) = .1587 (from z-score table)\r \n" ); document.write( "\n" ); document.write( "(ii) To determine the probability that more than 23 jars out of 100 weigh less than 227 grams, I would use a binomial distribution. More than 23 weighing less than 227 is the same as 76 or less weighing more than 227. \n" ); document.write( "P(> 23 of 100 weigh less than 227) = P(< or = 76 weighing more than 227) \n" ); document.write( "= binomcdf(100, .8413, 76) \n" ); document.write( "= .0225\r \n" ); document.write( "\n" ); document.write( "OR More than 23 weighing less than 227 is the complement of 23 or less weighing less than 227 \n" ); document.write( "P(> 23 of 100 weigh less than 227) = 1 - P(< or = 23 less than 227) \n" ); document.write( "= 1 - .9774 \n" ); document.write( "= .0225 \n" ); document.write( " |