document.write( "Question 1150678: “Best Fitness” Company is going to hold a stretching class with 15 registered students. From the previous records of stretching classes, the average absence rate per student is 5%.
\n" ); document.write( "(i) Calculate the probability that at most 13 students will attend the stretching class.
\n" ); document.write( "(ii) Given that at least 12 students attend the stretching class, calculate the probability that there will be at most 1 student absent.
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Algebra.Com's Answer #772348 by Boreal(15235)\"\" \"About 
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0.05 probability absent and 0.95 probability present\r
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\n" ); document.write( "\n" ); document.write( "probability at most is 13 is 1- probably (14 or 15) are there
\n" ); document.write( "that second term is 15C14*0.95^14*0.05=0.3658 plus 15C15*0.95^15=0.4633
\n" ); document.write( "They add to 0.8290 (rounding at end)
\n" ); document.write( "probability overall of 13 or fewer is 1-0.8290=0.1710 ANSWER\r
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\n" ); document.write( "\n" ); document.write( "probability of 12 attending is 15C12*0.95^12*0.05^3=0.0307
\n" ); document.write( "probability of 13 attending is 0.1348\r
\n" ); document.write( "\n" ); document.write( "0.0307
\n" ); document.write( "0.1348
\n" ); document.write( "0.3658
\n" ); document.write( "0.4633\r
\n" ); document.write( "\n" ); document.write( "Given that 12 attend, what is the probability it will be 14 or 15, is another way to phrase b.
\n" ); document.write( "That would be their sum over the sum of p(13,14,15)
\n" ); document.write( "0.8290/0.9638=0.8601
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