document.write( "Question 1150838: two number are in the ratio of 1:11 and the their sum is 15.find the numbers.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #772346 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"two numbers are in the ratio of 1:11\" which means that the second number is 11 times that of the first number.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If x is the first number, then 11*x = 11x is the second number. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"Their sum is 15\", so the two numbers add to 15.
\n" ); document.write( "A = first number = x
\n" ); document.write( "B = second number = 11x
\n" ); document.write( "A+B = 15
\n" ); document.write( "x+11x = 15
\n" ); document.write( "12x = 15
\n" ); document.write( "x = 15/12 ... divide both sides by 12
\n" ); document.write( "x = (5*3)/(4*3)
\n" ); document.write( "x = 5/4
\n" ); document.write( "x = 1.25
\n" ); document.write( "A = x
\n" ); document.write( "A = 1.25 is the first number\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use this x value to find the value of 11x
\n" ); document.write( "B = 11x
\n" ); document.write( "B = 11*1.25
\n" ); document.write( "B = 13.75 is the second number\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In decimal form, the two numbers are 1.25 and 13.75
\n" ); document.write( "In terms of fractions, the two numbers are 5/4 and 55/4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "note:
\n" ); document.write( "13.75 = 13 + 0.75 = 13 + 3/4 = 52/4 + 3/4 = (52+3)/4 = 55/4
\n" ); document.write( "
\n" ); document.write( "
\n" );