document.write( "Question 1150838: two number are in the ratio of 1:11 and the their sum is 15.find the numbers.\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #772346 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\"two numbers are in the ratio of 1:11\" which means that the second number is 11 times that of the first number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x is the first number, then 11*x = 11x is the second number. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"Their sum is 15\", so the two numbers add to 15. \n" ); document.write( "A = first number = x \n" ); document.write( "B = second number = 11x \n" ); document.write( "A+B = 15 \n" ); document.write( "x+11x = 15 \n" ); document.write( "12x = 15 \n" ); document.write( "x = 15/12 ... divide both sides by 12 \n" ); document.write( "x = (5*3)/(4*3) \n" ); document.write( "x = 5/4 \n" ); document.write( "x = 1.25 \n" ); document.write( "A = x \n" ); document.write( "A = 1.25 is the first number\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use this x value to find the value of 11x \n" ); document.write( "B = 11x \n" ); document.write( "B = 11*1.25 \n" ); document.write( "B = 13.75 is the second number\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In decimal form, the two numbers are 1.25 and 13.75 \n" ); document.write( "In terms of fractions, the two numbers are 5/4 and 55/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "note: \n" ); document.write( "13.75 = 13 + 0.75 = 13 + 3/4 = 52/4 + 3/4 = (52+3)/4 = 55/4 \n" ); document.write( " \n" ); document.write( " |