document.write( "Question 1150815: one brand of tires are normally distributed with a mean of 48,500 miles and a standard deviation of 5000 if the manufacturer is willing to replace no more than 10% of the tires, what should be the approximate number of miles for a warranty? \n" ); document.write( "

Algebra.Com's Answer #772299 by amarjeeth123(570) $\"\"$ $\"About$

You can put this solution on YOUR website!
P(Z < z*) = 0.10 has a z* = -1.282 [from Standard Normal table]\r
\n" ); document.write( "\n" ); document.write( "Answer = 48500 + (-1.282)(5000) = 42,090 miles for a warranty \n" ); document.write( "

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