document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150793>Question 1150793</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pls, I Need Ur Help In This Question, With Full Explaination.<BR>\n" );
document.write( "Find the equations whose perpendicular distance is of length 3 units and at 60(degree) from the x-axis. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #772247 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=772247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you're talking about the equation of a straight line, then i believe your answer will be y = sqrt(3) * x\r<BR>\n" );
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document.write( "you form a triangle with the vertex of the angle at the point (0,0).<BR>\n" );
document.write( "the angle is 60 degrees.<BR>\n" );
document.write( "your y-value is the height of the triangle.<BR>\n" );
document.write( "your x-value is the distance from the y-axis to the point where y = 3.<BR>\n" );
document.write( "your equation is tan(60) = y / x.<BR>\n" );
document.write( "when y = 3, the equation becomes tan(60) = 3/x<BR>\n" );
document.write( "solve for x to get x = 3 / tan(60) = 1.732050808.<BR>\n" );
document.write( "this this the same as x = sqrt(3).\r<BR>\n" );
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document.write( "therefore, you have 2 points on the line.<BR>\n" );
document.write( "they are (0,0) and (sqrt(3),3).\r<BR>\n" );
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document.write( "the slope intercept form of the equation of a straight line is y = mx + b.<BR>\n" );
document.write( "m is the slope and b is the y-intercept.<BR>\n" );
document.write( "when x = 0, y = 0 because that's the vertex of the angle formed so.<BR>\n" );
document.write( "your y-intercept is therefore equal to 0 and the equation becomes y = mx + 0 which becomes y = mx.\r<BR>\n" );
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document.write( "the slope is equal to (y2 - y1) / (x2 - x1)<BR>\n" );
document.write( "(x1,y1) = 0,0)<BR>\n" );
document.write( "(x2,y2) = (sqrt(3),3)<BR>\n" );
document.write( "(y2 - y1) / (x2 - x1) becomes (3 - 0) / (sqrt(3) - 0) = 3 / sqrt(3).<BR>\n" );
document.write( "3 / sqrt(3) * sqrt(3) / sqrt(3) =  3 * sqrt(3) / 3 = sqrt(3).<BR>\n" );
document.write( "your slope is sqrt(3).\r<BR>\n" );
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document.write( "your equation of the straight line becomes y = sqrt(3) * x.\r<BR>\n" );
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document.write( "when y = 3, solve for x to get x = 3 / sqrt(3) = 3 * sqrt(3) / 3 = sqrt(3) = 1.732050808 which rounds to 1.732 as shown on the graph.\r<BR>\n" );
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document.write( "here's my worksheet.\r<BR>\n" );
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document.write( "the top point on the right of the triangle is the point (sqrt(3), 3).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2019/122403.jpg\" alt=\"$$$\" >\r<BR>\n" );
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document.write( "here's the graph of the equation of y = sqrt(3) * x.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2019/122404.jpg\" alt=\"$$$\" >\r<BR>\n" );
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document.write( "i think your solution is that the equation of the line is y = sqrt(3) * x.\r<BR>\n" );
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document.write( "the domain is all real values of x.<BR>\n" );
document.write( "the range is all real values of y.\r<BR>\n" );
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