document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150774>Question 1150774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fraction that is bigger than 5/6 but smaller than 6/7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #772243 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=772243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Let me expand a bit on the method shown by tutor @ikleyn, in case you don't see why she did what she did.<br><BR>\n" );
document.write( "First, we will express the two given fractions with a common denominator:<br><BR>\n" );
document.write( "5/6 = (5/6)*(7/7) = 35/42<BR>\n" );
document.write( "6/7 = (6/7)*(6/6) = 36/42<br><BR>\n" );
document.write( "With a common denominator, we can get a fraction that is between the two given fractions if we can find another fraction with the same denominator and a numerator between the numerators of the given fractions.<br><BR>\n" );
document.write( "But there is no integer between the numerators of 35 and 36.<br><BR>\n" );
document.write( "So we next express both fractions as equivalent fractions, by multiplying numerator and denominator of both fractions by 2:<br><BR>\n" );
document.write( "35/42 = (35/42)*(2/2) = 70/84<BR>\n" );
document.write( "36/42 = (36/42)*(2/2) = 72/84<br><BR>\n" );
document.write( "And now we can find a fraction with denominator 84 that is between the two given fractions: 71/84<br><BR>\n" );
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