document.write( "Question 1150762: Stephen is 69 years younger than Wendy. 2 years ago, Wendy's age was 4 times Stephen's age. How old is Stephen now? \n" ); document.write( "
Algebra.Com's Answer #772212 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "Of course there are many good ways to set up this problem for solving.

\n" ); document.write( "Following is what I would do....

\n" ); document.write( "Let x be Stephen's age 2 years ago; then Wendy's age then was 4x.

\n" ); document.write( "The difference in their ages 2 years ago was then 4x-x = 3x.

\n" ); document.write( "The difference in their ages (now, and 2 years ago, and always) is 69 years.

\n" ); document.write( "So 2 years ago the difference in their ages was 3x = 69.

\n" ); document.write( "So 2 years ago Stephen's age was x = 69/3 = 23 and Wendy's age was 4x = 92.

\n" ); document.write( "So now Stephen's age is 23+2 = 25 years.

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