document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106170>Question 106170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the height of a triangle is five feet less than two times the base. If the area is 75 square feet find the base and height. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77219 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the height of a triangle is five feet less than two times the base. If the area is 75 square feet find the base and height.<BR>\n" );
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document.write( "Formula: Area = (1/2)(base)(height)<BR>\n" );
document.write( "75 = (1/2)(x)(2x-5)<BR>\n" );
document.write( "150 = x(2x-5)<BR>\n" );
document.write( "2x^2-5x-150 = 0<BR>\n" );
document.write( "(2x+15) (x-10)= 0<BR>\n" );
document.write( "x=-15/2 ; x=10<BR>\n" );
document.write( "Only x=10 is realistic (base = 10 ft.)<BR>\n" );
document.write( "Then height = 2*10-5 = 15 ft.<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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