document.write( "Question 1150745: A laptop computer is purchased for $2600. Each year, its value is 80% of its value the year before. After how many years will the laptop computer be worth $900 or less? \n" ); document.write( "
Algebra.Com's Answer #772164 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A laptop computer is purchased for $2600. Each year, its value is 80% of its value the year before. After how many years will the laptop computer be worth $900 or less?\r
\n" ); document.write( "\n" ); document.write( "-----------------
\n" ); document.write( "After 1 year, it's $2600*0.8 = $2080
\n" ); document.write( "After 2 years, it's $2080*0.8 = $1664
\n" ); document.write( "etc
\n" ); document.write( "-------------
\n" ); document.write( "FV = $2600*(0.8^t) --- t in years
\n" ); document.write( "$900 = $2600*0.8^t
\n" ); document.write( "9/26 = 0.8^t
\n" ); document.write( "Log(9/26) = t*log(0.8)
\n" ); document.write( "t = log(9/26)/log(0.8) = ~4.7542 years
\n" ); document.write( "---> 5 years
\n" ); document.write( "=================
\n" ); document.write( "Not a well stated problem.
\n" ); document.write( "The answer can be \"after 10 years\" or after any # of years t > 4 (t as an integer).
\n" ); document.write( "You can answer \"after 1000 years\" and not be wrong.
\n" ); document.write( "
\n" );