document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150673>Question 1150673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which one of these circles has the <B><I>smallest</I></B> area?\r<BR>\n" );
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document.write( "<LI>x² + y² = 12</LI><BR>\n" );
document.write( "<LI>(x - 2)² + y² = 8</LI><BR>\n" );
document.write( "<LI>(x + 1)² + (y+3)² = 6</LI><BR>\n" );
document.write( "<LI>(x + 8)² + (y - 9)² = 3</LI><BR>\n" );
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document.write( "(The only way to find out is to find the area of each of these answer choices, and then select the SMALLEST area, by using these formulas:)\r<BR>\n" );
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document.write( "(x + h)² + (y + k)² = r²\r<BR>\n" );
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document.write( "<B>Center</B> = (h, k)<BR>\n" );
document.write( "<B>Radius</B> = √(r²) or r </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #772090 by </B><A HREF=/tutors/aboutme.mpl?userid=Kimani><B>Kimani(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Kimani><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Kimani><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=772090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So, basically, when I placed these values on my TI-84 Plus graphing-calculator from Texas Instruments...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Circle%280%2C0%2C12%29%3ACircle%282%2C0%2C8%29%3ACircle%281%2C3%2C6%29%3ACircle%288%2C9%2C3%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "...and then pressed the [ENTER] key, the graph automatically draws 4 different circles that are roughly interlinking each other—but in different sizes—and as I watched each step carefully, I have recognized that the smallest circle is the one with the radius of 3.\r<BR>\n" );
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document.write( "Although the center is located at coordinates (8, 9), the radius of the circle is measured 3 units for all 360 angles, no matter what the selected angle.\r<BR>\n" );
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document.write( "So, therefore, <I>(x + 8)² + (y - 9)² = 3</I> is the circle that has the smallest area, or radius. </SPAN>\n" );
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