document.write( "Question 1150651: The Jones family drove to Kankakee in 5 hours and returned in 4 hours. Their rate on the return trip was 9 mph faster than their rate going. Find their rate going \n" ); document.write( "
Algebra.Com's Answer #772054 by josgarithmetic(39631)\"\" \"About 
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document.write( "                 SPEED       TIME      DISTANCE\r\n" );
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document.write( "GOING             r            5          d\r\n" );
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document.write( "RETURN          r+9            4          d\r\n" );
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\n" ); document.write( "Same distance d both going and returning.
\n" ); document.write( "\"5r=4%28r%2B9%29\"
\n" ); document.write( "Solve.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28r=36%29\" \n" ); document.write( "
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