document.write( "Question 1150645: How many liters of a 70
\n" ); document.write( "​%
\n" ); document.write( "acid solution must be mixed with a 20
\n" ); document.write( "​%
\n" ); document.write( "acid solution to get 350
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #772049 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Description is incomplete.
\n" ); document.write( "350 Liters of what finished percent acid?\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If result is 350 liters of some number p percent acid, then
\n" ); document.write( "x liters of 70%
\n" ); document.write( "350-x liters of 20%
\n" ); document.write( "\"70x%2B20%28350-x%29=p%2A350\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"7x%2B2%28350-x%29=35p\"
\n" ); document.write( "\"7x%2B2%2A350-2x=35p\"
\n" ); document.write( "\"5x%2B2%2A350=35p\"
\n" ); document.write( "\"5x=35p-2%2A350\"
\n" ); document.write( "\"x=7p-140\"
\n" ); document.write( "You finish from here. You need to know the given finished percent acid, p; and then you can evaluate x and 350-x.
\n" ); document.write( "
\n" );