document.write( "Question 106113: Well im doing homework and i have the problem -5k-19=5-13k Well my teacher told us that you have to put the k's as one. We were doing a problem in class and she was showing a problem where you would subtract one from another...like
\n" ); document.write( "-5k-13k but i thought you had to do the oppisite to where if in the equation it was subtracting you had to add? So if you could help i would really appiciate it.
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Algebra.Com's Answer #77202 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"-5k-19=5-13k\"
\n" ); document.write( "When you solve an equation, you have to move all of the known terms (numbers) on one side and all of the unknown (k) terms on the other.
\n" ); document.write( "Let's move all the k terms to the left hand side and all the non-k terms to the right hand side.
\n" ); document.write( "Remember, whatever you do to one side of the equation, you have to do to the other side of the equation.
\n" ); document.write( "\"-5k-19=5-13k\"
\n" ); document.write( "To get rid of the (-13k) on the right hand side, I have to add the additive inverse of (-13k).
\n" ); document.write( "The additive inverse of x is -x be because x+(-x)=0.
\n" ); document.write( "The additive inverse of (-13k) is -(-13k).
\n" ); document.write( "Negative times negative is positive or -(-13k)=13k.
\n" ); document.write( "Add 13k to both sides of the equation.
\n" ); document.write( "\"-5k-19=5-13k\"
\n" ); document.write( "\"-5k-19%2B13k=5cross%28-13k%29%2Bcross%2813k%29\"
\n" ); document.write( "\"-5k-19%2B13k=5\"
\n" ); document.write( "\"13k-5k-19=5\"
\n" ); document.write( "\"8k-19=5\"
\n" ); document.write( "To get rid of the -19 on the left hand side, use the additive inverse of -19.
\n" ); document.write( "The additive inverse of (-19) is -(-19) or (19).
\n" ); document.write( "Add 19 to both sides of the equation.
\n" ); document.write( "\"8k+%28cross%28-19%29%29%2Bcross%2819%29=5%2B19\"
\n" ); document.write( "\"8k=24\"
\n" ); document.write( "Now to get rid of the 8 in front of k, you need to use the multiplicative inverse of 8.
\n" ); document.write( "The multiplicative inverse of x is 1/x since \"x%2A%281%2Fx%29=1\".
\n" ); document.write( "The multiplicative inverse of 8 is 1/8.
\n" ); document.write( "Multiply both sides of the equation by 1/8.
\n" ); document.write( "\"8k%2A1%2F8=24%2A1%2F8\"
\n" ); document.write( "\"%288%2F8%29k=24%2F8\"
\n" ); document.write( "\"k=3\"
\n" ); document.write( "Check your answer in your original equation.
\n" ); document.write( "\"-5k-19=5-13k\"
\n" ); document.write( "\"-5%283%29-19=5-13%283%29\"
\n" ); document.write( "\"-15-19=5-39\"
\n" ); document.write( "\"-34=-34\"
\n" ); document.write( "Good answer.
\n" ); document.write( "Since you get an answer that makes sense, your solution is good.
\n" ); document.write( "k=3.
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