document.write( "Question 1150626: Using a 4:3 ratio, determine the side lengths of a TV whose diagonal length is 55 inches. \n" ); document.write( "

Algebra.Com's Answer #772011 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = the length
\n" ); document.write( "Let $\"+y+\"$ = the width
\n" ); document.write( "----------------------------
\n" ); document.write( "(1) $\"+4%2F3+=+x%2Fy+\"$
\n" ); document.write( "(2) $\"+x%5E2+%2B+y%5E2+=+55%5E2+\"$
\n" ); document.write( "------------------------------
\n" ); document.write( "(1) $\"+x+=+%28+4%2F3+%29%2Ay+\"$
\n" ); document.write( "(2) $\"+x%5E2+%2B+y%5E2+=+55%5E2+\"$
\n" ); document.write( "(2) $\"+%28+%284%2F3%29%2Ay+%29%5E2+%2B+y%5E2+=+3025+\"$
\n" ); document.write( "(2) $\"+%28+16%2F9+%29%2Ay%5E2+%2B+%289%2F9%29%2A+y%5E2+=+3025+\"$
\n" ); document.write( "(2) $\"+%28+25%2F9+%29%2Ay%5E2+=+3025+\"$
\n" ); document.write( "(2) $\"+y%5E2+=+%28+9%2F25+%29%2A3025+\"$
\n" ); document.write( "(2) $\"+y+=+%28+3%2F5%29%2A55+\"$
\n" ); document.write( "(2) $\"+y+=+33+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+x+=+%28+4%2F3+%29%2Ay+\"$
\n" ); document.write( "(1) $\"+x+=+%28+4%2F3+%29%2A33+\"$
\n" ); document.write( "(1) $\"+x+=+44+\"$
\n" ); document.write( "---------------------------
\n" ); document.write( "The sides are 33 in and 44 in
\n" ); document.write( "-------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+44%5E2+%2B+33%5E2+=+55%5E2+\"$
\n" ); document.write( " $\"+1936+%2B+1089+=+3025+\"$
\n" ); document.write( " $\"+3025+=+3025+\"$
\n" ); document.write( "OK \n" ); document.write( "

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