document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150615>Question 1150615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> divide 29 in to two parts so that the sum of the sqare of the parts is 425 .find the value of each parts. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #772007 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=772007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> divide 29 in to two parts so that the sum of the sqare of the parts is 425 .find the value of each parts.<BR>\n" );
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document.write( "x + y = 29<BR>\n" );
document.write( "x^2 + y^2 = 425<BR>\n" );
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document.write( "x^2 + (29 - x)^2 = 425<BR>\n" );
document.write( "2x^2 - 58x + 841 = 425<BR>\n" );
document.write( "2x^2 - 58x + 416 = 0<BR>\n" );
document.write( "x^2 - 29x + 208 = 0<BR>\n" );
document.write( "etc </SPAN>\n" );
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