document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15596>Question 15596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with this question?\r<BR>\n" );
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document.write( "At the end of the first year an account earning 3% interest earns $126 in interest.  How much money was deposited in the account at the start of the year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7720 by </B><A HREF=/tutors/aboutme.mpl?userid=pwac><B>pwac(253)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pwac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= money at start of year<BR>\n" );
document.write( "In the year the money has has increased to(100%+3%)of x<BR>\n" );
document.write( "That is 103% of$x which is the same as saying 1.03 times x<BR>\n" );
document.write( " So 1.03x=$126 Divide $126 by 1.03 which gives<BR>\n" );
document.write( "x=$122.33\r<BR>\n" );
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document.write( "Pete </SPAN>\n" );
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