document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150582>Question 1150582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 1854​, a person sold a house to a lady for ​$30. If the lady had put the ​$30 into a bank account paying 5​% ​interest, how much would the investment have been worth in the year 2009 if interest were compounded in the following​ ways?<BR>\n" );
document.write( "a. monthly                 b. continuously<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #771974 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=771974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In 1854​, a person sold a house to a lady for ​$30. If the lady had put the ​$30 into a bank account paying 5​% ​interest, how much would the investment have been worth in the year 2009 if interest were compounded in the following​ ways?<BR>\n" );
document.write( "------<BR>\n" );
document.write( "2009 - 1854 = 155 years (from Jan to Jan, the times of years not stated)<BR>\n" );
document.write( "a. monthly                 <BR>\n" );
document.write( "155*12 = 1860 months<BR>\n" );
document.write( "FV = $30*(1 + 0.05/12)^1860<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "b. continuously<BR>\n" );
document.write( "FV = $30*e^(0.05*155)\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );