document.write( "Question 1150586: Warren went on a bike ride of 60 miles. He realized that if he had gone 25 mph faster, he would have arrived 10 hours sooner. How fast did he actually ride?
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Algebra.Com's Answer #771972 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "               SPEED       TIME       DISTANCE\r\n" );
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document.write( "Actual          r          60/r         60\r\n" );
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document.write( "IF            r+25         60/(r+25)    60\r\n" );
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document.write( "Difference                 10\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solve for r in $\"60%2Fr-60%2F%28r%2B25%29=10\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Simplified, same as $\"6%2Fr-6%2F%28r%2B25%29=1\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Work through the algebra should show a step, $\"r%5E2%2B25r-150=0\"$ ;
\n" ); document.write( "discriminant is $\"35%5E2\"$ ;\r
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\n" ); document.write( "\n" ); document.write( " $\"r=%28-25%2B35%29%2F2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28r=5%29\"$ \n" ); document.write( "

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