document.write( "Question 1150570: today the father is 51 years and his son is 9 years . In how many years the father will be four times as old as his son? \n" ); document.write( "
Algebra.Com's Answer #771962 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The difference in their ages is 51-9 = 42 years.

\n" ); document.write( "When the father is 4 times as old as his son, their ages will be 4x and x; the difference will be 3x.

\n" ); document.write( "3x = 42
\n" ); document.write( "x = 42/3 = 14

\n" ); document.write( "The father will be 4 times as old as his son when the son is x=14 and the father is 4x=56.

\n" ); document.write( "Since the father is now 51, that will be 5 years from now.

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