document.write( "Question 1150570: today the father is 51 years and his son is 9 years . In how many years the father will be four times as old as his son? \n" ); document.write( "
Algebra.Com's Answer #771962 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The difference in their ages is 51-9 = 42 years. \n" ); document.write( "When the father is 4 times as old as his son, their ages will be 4x and x; the difference will be 3x. \n" ); document.write( "3x = 42 \n" ); document.write( "x = 42/3 = 14 \n" ); document.write( "The father will be 4 times as old as his son when the son is x=14 and the father is 4x=56. \n" ); document.write( "Since the father is now 51, that will be 5 years from now. \n" ); document.write( " \n" ); document.write( " |