document.write( "Question 1150579: A farmer raises chickens and cows. he has a total of 34 animals in his
\n" ); document.write( "barnyard. His six year old son came in one day all excited saying,\"Daddy,
\n" ); document.write( "Daddy, did you know all of your animals have a total of 110 legs. How many
\n" ); document.write( "chickens and how many cows does the farmer have> \n" ); document.write( "

Algebra.Com's Answer #771957 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!
a farmer raises chickens and cows. he has a total of 34 animals in his
\n" ); document.write( "barnyard. his six year old son came in one day all excited saying,\"Daddy,
\n" ); document.write( "daddy, did you know all of your animals have a total of 110 legs.
\n" ); document.write( "

\r\n" );
document.write( "Without using algebra:\r\n" );
document.write( "If they were all chickens, there would be twice as many legs as heads or 68\r\n" );
document.write( "legs.  So all the extra legs, which is 110-68=42 extra legs, belong to the\r\n" );
document.write( "cows.  So since a cow has 2 extra legs that a chicken doesn't have, the number\r\n" );
document.write( "of cows is half of 42 or 21. So the number of chickens is 34-21 or 13.\r\n" );
document.write( "\r\n" );
document.write( "Using algebra:\r\n" );
document.write( "\r\n" );
document.write( "Let x = the number of chickens and y = the number of cows.\r\n" );
document.write( "\r\n" );
document.write( "CHICKENS + COWS = 34 ANIMALS\r\n" );
document.write( "CHICKEN LEGS + COW LEGS = 110\r\n" );
document.write( "\r\n" );
document.write( " x +  y =  34\r\n" );
document.write( "2x + 4y = 110\r\n" );
document.write( "\r\n" );
document.write( "Solve that system and get the same answer.\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( " \n" ); document.write( "

\n" );