document.write( "Question 1150398: Given: m∠A = α = 42º
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Algebra.Com's Answer #771949 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Given: m∠A = α = 42º\r\n" );
document.write( "       Area of ∆ACK = 50 c\r\n" );
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document.write( "∆ACK is a right triangle because it is inscribed in a semicircle.\r\n" );
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document.write( "Therefore its area is half the product of its legs:\r\n" );
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document.write( "\"A=expr%281%2F2%29%28AC%29%28CK%29\"\r\n" );
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document.write( "\"AC%2FAK=cos%2842%5Eo%29\", \"AC=AK%2Acos%2842%5Eo%29\",\r\n" );
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document.write( "\"CK%2FAK=sin%2842%5Eo%29\", \"CK=AK%2Asin%2842%5Eo%29\",\r\n" );
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document.write( "\"AK=diameter=2R\"\r\n" );
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document.write( "\"AC=2R%2Acos%2842%5Eo%29\",  \"CK=2R%2Asin%2842%5Eo%29\",\r\n" );
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document.write( "Substituting in \r\n" );
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document.write( "\"A=expr%281%2F2%29%28AC%29%28CK%29\"\r\n" );
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document.write( "\"50=expr%281%2F2%29%282R%2Acos%2842%5Eo%29%5E%22%22%29%282R%2Asin%2842%5Eo%29%5E%22%22%29\"\r\n" );
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document.write( "You finish.  Simplify that and solve for R.\r\n" );
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document.write( "Answer: R ≈ 7.090515777\r\n" );
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document.write( "Edwin

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