document.write( "Question 1150569: ten years ago mike was four times old as lisa, now he is twice as old as liza, how old are they now? \n" ); document.write( "

Algebra.Com's Answer #771946 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "If x is Lisa's present age, then Mike's present age is 2x years.\r\n" );
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document.write( "Ten years ago . . . \r\n" );
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document.write( "    4*(x - 10) = 2x-10\r\n" );
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document.write( "Simlify and solve\r\n" );
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document.write( "    4x - 40 = 2x - 10\r\n" );
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document.write( "    4x - 2x = 40- 10\r\n" );
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document.write( "    2x      = 30\r\n" );
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document.write( "     x      = 30/2 = 15.\r\n" );
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document.write( "ANSWER.  Lisa is 15 years old.  Mike is 2*15 = 30 years old.\r\n" );
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