document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150467>Question 1150467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If tn =  10/3 − n/3 , find t1, t2, t3 and tn+1 . Express tn+1−tn in its simplest form.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #771940 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=771940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> T[n] = 10/3 - n/3.\r<BR>\n" );
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document.write( "T[1] = 10/3 - 1/3 = 9/3\r<BR>\n" );
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document.write( "T[2] = 10/3 - 2/3 = 8/3\r<BR>\n" );
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document.write( "T[3] = 10/3 - 3/3 = 7/3\r<BR>\n" );
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document.write( "T[n+1] = 10/3 - (n+1)/3\r<BR>\n" );
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document.write( "T[n+1] - T[n] = 10/3 - (n+1)/3 - (10/3 - n/3)<BR>\n" );
document.write( "simplify this to get:<BR>\n" );
document.write( "T[n+1] - T[n] = 10/3 - (n+1)/3 - 10/3 + n/3<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "T[n+1] - T[n] = -(n+1)/3 + n/3 = (-n - 1 + n) / 3 = -1/3\r<BR>\n" );
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document.write( "for example:\r<BR>\n" );
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document.write( "T3 = 10/3 - 3/3 = 7/3<BR>\n" );
document.write( "T2 = 10/3 - 2/3 = 8/3\r<BR>\n" );
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document.write( "if you let T[n] = T[2] and, if you let T[n+1] = T[3], then you get:<BR>\n" );
document.write( "T[n+1] - T[n] = T[3] - T[2] = (10/3 - 3/3) - (10/3 - 2/3) = 7/3 - 8/3 = -1/3.\r<BR>\n" );
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document.write( "this is correct according to the formula, as far as i can tell.\r<BR>\n" );
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document.write( "further, if you look at T[1] and T[2] and T[3], you will see that each succeeding value is 1/3 less than the preceding value by 1/3.\r<BR>\n" );
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