document.write( "Question 1150524: 500 feet of fencing is available to enclose a rectangular lot along side of highway 65. Cal trans will supply the fencing for the side along the highway, so only 3 sides are needed. What dimensions will produce an area of 40,000 square feet? What is the maximum area that can be enclosed? \n" ); document.write( "
Algebra.Com's Answer #771892 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let the side perpendicular to the highway = \"+w+\"
\n" ); document.write( "\"+500+-+2w+\" = the length of the side parallel to the highway
\n" ); document.write( "Let \"+A+\" = the area of the lot
\n" ); document.write( "-----------------------------------
\n" ); document.write( "\"+A+=+w%2A%28+500+-+2w+%29+\"
\n" ); document.write( "\"+A+=+-2w%5E2+%2B+500w+\"
\n" ); document.write( "Use the formula for the vertex:
\n" ); document.write( "\"+w%5Bpk%5D+=+-500%2F%28+2%2A%28-2%29%29+\"
\n" ); document.write( "\"+w%5Bpk%5D+=+125+\"
\n" ); document.write( "Plug this result back into equation
\n" ); document.write( "\"+A%5Bmax%5D+=+-2%2A%28125%29%5E2+%2B+500%2A125+\"
\n" ); document.write( "\"+A%5Bmax%5D+=+31250+\" ft2
\n" ); document.write( "Since 40000 ft2 is greater than the maximum area
\n" ); document.write( "this can't be enclosed with 500 ft of fencing
\n" ); document.write( "Here's the plot:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-100%2C+300%2C+-3500%2C+35000%2C+-2x%5E2+%2B+500x+%29+\"
\n" ); document.write( "
\n" );