document.write( "Question 1150520: The speed of a stream is 5 mph. a boat travels 88 mi downstream in the same time that it takes to travel 44 mi upstream, what is the speed the boat in still water? \n" ); document.write( "

Algebra.Com's Answer #771882 by ikleyn(52798) $\"\"$ $\"About$

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document.write( "Let v be the speed of the boat in still water, in miles per hour.\r\n" );
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document.write( "Then the effective rate traveling downstream is (v+5) mph;\r\n" );
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document.write( "     the effective rate traveling upstream   is (v-5) mph.\r\n" );
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document.write( "The \"time\" equation is\r\n" );
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document.write( "     = ,\r\n" );
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document.write( "according to the condition.\r\n" );
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document.write( "To solve it, cancel the factor 44 in both side, first. You will get\r\n" );
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document.write( "     = .\r\n" );
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document.write( "Cross multiply and simplify\r\n" );
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document.write( "    2*(v-5) = v+5\r\n" );
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document.write( "    2v - 10 = v + 5\r\n" );
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document.write( "    v = 15.\r\n" );
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document.write( "ANSWER.  The boat rate in still water is 15 miles per hour.\r\n" );
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