document.write( "Question 1150476: Rommie is 10 years older than Lady. In 10 years, the product of their ages is twice the product of their present ages. How old is Lady 5 years from now? \n" ); document.write( "
Algebra.Com's Answer #771854 by MathTherapy(10552)\"\" \"About 
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Rommie is 10 years older than Lady. In 10 years, the product of their ages is twice the product of their present ages. How old is Lady 5 years from now?
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NO WAY should this problem be that complex and \"novel-like\" as the other person makes it out to be.
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document.write( "CORRECT APPROACH:
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document.write( "Let Lady's current age be L
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document.write( "Then Rommie's is L + 10
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document.write( "Based on the given info., (L + 10)(L + 1O + 10) = 2L(L + 10)
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document.write( "(L + 10)(L + 20) = 2L(L + 10) 
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document.write( "L + 20 = 2L ----- Factoring out GCF, L + 10
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document.write( "20 = 2L - L
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document.write( "20 = L, or Lady's current age
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document.write( "With Lady being 20, in 5 years, she'll be: \"highlight_green%28matrix%281%2C4%2C+20+%2B+5%2C+%22=%22%2C+25%2C+years-old%29%29\" \n" );
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