document.write( "Question 1150458: On a day when visibility was limited to 1700m, a ship of the Blue Line was traveling west, on a parallel course to a ship of the White Line travelling east, with the courses 800m apart. The Blue Line ship’s velocity was 8 km/h. If the ships were in sight of each other for 15 minutes, what was the velocity, in km/h, of the White Line ship? \n" ); document.write( "

Algebra.Com's Answer #771839 by ikleyn(52803) $\"\"$ $\"About$

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document.write( "The configuration, when they see each other for the first time, is the right angled triangle with one leg of 800 meters \r\n" );
document.write( "and the hypotenuse of 1700 meters.\r\n" );
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document.write( "Then the other leg is   = 1500 meters  ((8-15-17 right angled triangle).\r\n" );
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document.write( "The configuration, when they see each other at the last time, is similar, but reversed, right angled (800-1500-1700 meters) triangle.\r\n" );
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document.write( "So, moving in parallel courses, they will see each other until they together will cover \r\n" );
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document.write( "        2*1500 meters = 3000 meters = 3 kilometers cumulatively.\r\n" );
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document.write( "Let \"v\" be velocity under the question.\r\n" );
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document.write( "Then we have this equation for cumulative distance\r\n" );
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document.write( "    0.25*8 + 0.25*v = 2*3  kilometers.   (1)\r\n" );
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document.write( "Here 0.25 is 0.25 of an hour, or 15 minutes.\r\n" );
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document.write( "From equation (1),  \r\n" );
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document.write( "    0.25v = 2*3 - 0.25*8 = 6 - 2 = 4 kilometers,\r\n" );
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document.write( "        v                        =  = 16 km/h.    ANSWER\r\n" );
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document.write( "ANSWER.   Velocity of the White Line ship is  16  kilometers per hour.\r\n" );
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