document.write( "Question 1150462: Two numbers are randomly selected (with replacements) from the first 12 positive integers. What is the probability that the sum of these two numbers is 10? \n" ); document.write( "
Algebra.Com's Answer #771835 by ikleyn(52780)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "The number of all possible outcomes is  12*12 = 144.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    It is the number of all pairs (a,b) with integers \"a\" and \"b\" from 1 to 12 inclusive.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The favorable pairs are (1,9), (2,8), (3,7), (4,6), (5,5), (6,4), (7,3), (8,2) and (9,1).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The number of favorable pairs is 9.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The probability under the question is  P = \"9%2F144\" = \"1%2F16\".    ANSWER\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );