document.write( "Question 1150432: Two circles are tangent to each other at A and the centre of the larger circle is at C. The lines AB and FC are perpendicular diameters of the larger circle. If BD = 9 cm and FE = 5 cm, then what is the radius of the smaller circle, in centimeters?
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Algebra.Com's Answer #771831 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The statement of the problem is faulty; but the intent is clear. FC is a radius, not a diameter; let G be the point on the large circle that makes FG a diameter. \n" ); document.write( "Let H be the other point of intersection of the small circle with diameter FG. \n" ); document.write( "Let x be the length of segment CD. \n" ); document.write( "Since BD = 9, the radius of the large circle is x+9. In particular, AC = 9 \n" ); document.write( "Since EF = 5, CE = CH = x+4.. \n" ); document.write( "AD and EH are chords of the small circle, intersecting at C. From the theorem about the lengths of the pieces of two intersecting chords in a circle, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The diameter of the small circle is x + (x+9) = 2x+9 = 41. \n" ); document.write( "So the radius of the small circle is 20.5. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |