document.write( "Question 1150453: A 3 by 3 by 3 cube has three holes, each with a 1 by 1 cross-section running from the centre of
\n" ); document.write( "each face to the centre of the opposite face. What is the total surface area (in square units) of the
\n" ); document.write( "resulting solid? \n" ); document.write( "

Algebra.Com's Answer #771829 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "The surface area of the original cube is/was  6*(3*3) = 6*9 = 54 square unit.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "After 3 holes were made, we should subtract  6*(1*1) = square units for/(or from) 6 faces;\r\n" );
document.write( "\r\n" );
document.write( "and add 6 times 4 square units (in total 6*4 = 24 square units) for six  1 x 1 x 1  small empty cubes.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So, the ANSWER is  54 - 6 + 24 = 72 square units.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );