document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1150460>Question 1150460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A container filled with 30 litres of wine had 5 litres of the wine removed. To fill the container, 5 liters of water was added. The next day 12 litres of the mixture was removed, and replaced with an equal amount of water. What fraction of the final mixture was water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #771826 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=771826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"times\" color=\"black\" size=\"3\"><BR>\n" );
document.write( "Step 1) Remove 5 liters of wine. <BR>\n" );
document.write( "Mix A: 30 L of wine, 0 L of water<BR>\n" );
document.write( "Mix B: 25 L of wine, 0 L of water\r<BR>\n" );
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document.write( "Step 2) Add 5 liters of water.<BR>\n" );
document.write( "Mix B: 25 L of wine, 0 L of water<BR>\n" );
document.write( "Mix C: 25 L of wine, 5 L of water\r<BR>\n" );
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document.write( "Once we get to mix C, the fractional amount of wine is 5/6 because<BR>\n" );
document.write( "25/30 = 5/6<BR>\n" );
document.write( "The first fraction is in the form A/B<BR>\n" );
document.write( "where <BR>\n" );
document.write( "A = amount of wine in liters<BR>\n" );
document.write( "B = total amount of mixture (water+wine)<BR>\n" );
document.write( "The second fraction is the reduced version of 25/30.\r<BR>\n" );
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document.write( "Step 3) Remove 12 liters of liquid (from mix C) \r<BR>\n" );
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document.write( "5/6 of the amount of mix C is composed of wine. So 5/6 of the amount of stuff we remove (12 L) is expected to be wine. The rest is water.\r<BR>\n" );
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document.write( "5/6 of 12 = (5/6)*12 = 10 liters of wine is removed<BR>\n" );
document.write( "12-10 = 2 liters of water is removed as well\r<BR>\n" );
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document.write( "Mix C: 25 L of wine, 5 L of water<BR>\n" );
document.write( "Mix D: 15 L of wine, 3 L of water<BR>\n" );
document.write( "Going from mix C to mix D, I removed 10 liters of wine and removed 2 liters of water\r<BR>\n" );
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document.write( "Step 4) Add 12 liters of pure water <BR>\n" );
document.write( "Mix D: 15 L of wine, 3 L of water<BR>\n" );
document.write( "Mix E: 15 L of wine, 15 L of water\r<BR>\n" );
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document.write( "(15 L of water)/(15 L of water+15 L of wine) = 15/30 = 1/2 of mix E is water\r<BR>\n" );
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document.write( "<font size=4 color=red>Answer: 1/2</font><BR>\n" );
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