document.write( "Question 1150379: solve $\"x%5E2%2B3=38%2B2x\"$ \n" ); document.write( "

Algebra.Com's Answer #771767 by Theo(13342) $\"\"$ $\"About$

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equation to solve is x^2 + 3 = 38 + 2x
\n" ); document.write( "subtract 38 from both sides of the equation and subtract 2x from both sides of the equation to get:
\n" ); document.write( "x^2 + 3 - 38 - 2x = 0
\n" ); document.write( "combine liketerms to get:
\n" ); document.write( "x^2 - 35 - 2x = 0
\n" ); document.write( "rearrange the terms in descending order of degree to get:
\n" ); document.write( "x^2 - 2x - 35 = 0
\n" ); document.write( "factor this quadratic equation to get:
\n" ); document.write( "(x - 7) * (x + 5) = 0
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 7 or x = -5
\n" ); document.write( "when x = 7, x^2 - 2x - 35 = 0 becomes 49 - 14 - 35 = 0 which becomes 49 - 49 = 0 which becomes 0 = 0, confirming that x = 7 is one of the solutions.
\n" ); document.write( "when x = -5, x^2 - 2x - 35 = 0 becomes 25 + 10 - 35 = 0 which becomes 35 - 35 = 0 which becomes 0 = 0, confirming that x = -5 is one of the solutions.
\n" ); document.write( "your solution is that x = 7 or x = -5.\r
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