document.write( "Question 1150353: Records indicate that 30% of all students on a university campus are female. Also 20% of the females are \"A\" students, and 70% of the males are \"A\" students. If an \"A\" student is selected at random, what is the probability that the student is female? \n" ); document.write( "
Algebra.Com's Answer #771730 by ikleyn(52778)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Let N be the total of students on the University.\r\n" );
document.write( "\r\n" );
document.write( "Of them, 0.3N students are females and 0.7N students are males.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The total of  females \"A\" students is  0.2*0.3*N = 0.06N                           (1)\r\n" );
document.write( "\r\n" );
document.write( "The total of \"A\" students is  0.2*0.3*N + 0.7*0.7N = (0.06+0.49)*N = 0.55N.        (2)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Thus the answer to the problem's question is the ratio  (1) to (2)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    P = \"%280.06N%29%2F%280.55N%29\" = \"0.06%2F0.55\".    ANSWER\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );