document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106088>Question 106088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In planning for a new item, a manufacturer assumes that the number of items produced x and the cost in dollars C of producing these items are related by a linear equation.  Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce.  Find the equation that relates C and x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77172 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce. Find the equation that relates C and x.<BR>\n" );
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document.write( "You have two points: (100,10000) and (300,22000)<BR>\n" );
document.write( "slope = [22000-10000]/[300-100] = 12000/200 = 60<BR>\n" );
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document.write( "Form is: Cost = slope*# of items + b<BR>\n" );
document.write( "Solve for b by substituting as follows:<BR>\n" );
document.write( "10000= 60*100 + b<BR>\n" );
document.write( "b = 10000-6000= 4000<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "Cost = 60(# of items) + 4000<BR>\n" );
document.write( "C(x) = 60x + 4000<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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