document.write( "Question 1150319: Miguel went on a bike ride of 24 miles. He realized that if he had gone 6 mph faster, he would have arrived 9 hours sooner. How fast did he actually ride? \n" ); document.write( "
Algebra.Com's Answer #771696 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+r+\" = his normal rate in mi/hr
\n" ); document.write( "Let \"+t+\" = his normal time in hrs
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "Normal rate:
\n" ); document.write( "(1) \"+24+=+r%2At+\"
\n" ); document.write( "Faster rate:
\n" ); document.write( "(2) \"+24+=+%28+r+%2B+6+%29%2A%28+t+-+9+%29+\"
\n" ); document.write( "------------------------------------
\n" ); document.write( "(1) \"+t+=+24%2Fr+\"
\n" ); document.write( "(2) \"+24+=+%28+r+%2B+6+%29%2A%28+24%2Fr+-+9+%29+\"
\n" ); document.write( "(2) \"+24+=+24+%2B+144%2Fr+-+9r+-+54+\"
\n" ); document.write( "(2) \"+0+=+144%2Fr+-+9r+-+54+\"
\n" ); document.write( "(2) \"+144%2Fr+=+9r+%2B+54+\"
\n" ); document.write( "(2) \"+144+=+9r%5E2+%2B+54r+\"
\n" ); document.write( "(2) \"+16+=+r%5E2+%2B+6r+\"
\n" ); document.write( "(2) \"+r%5E2+%2B+6r+-+16+=+0+\"
\n" ); document.write( "(2) \"+%28+r+%2B+8+%29%2A%28+r+-+2+%29+=+0+\"
\n" ); document.write( "(2) \"+r+=+2+\" ( can't use the negative result )
\n" ); document.write( "His normal rate was 2 mi/hr
\n" ); document.write( "-------------------------------
\n" ); document.write( "check answer:
\n" ); document.write( "(1) \"+24+=+r%2At+\"
\n" ); document.write( "(1) \"+24+=+2%2At+\"
\n" ); document.write( "(1) \"+t+=+12+\" hrs
\n" ); document.write( "and
\n" ); document.write( "(2) \"+24+=+%28+r+%2B+6+%29%2A%28+t+-+9+%29+\"
\n" ); document.write( "(2) \"+24+=+%28+2+%2B+6+%29%2A%28+t+-+9+%29+\"
\n" ); document.write( "(2) \"+24+=+8%2A%28+t+-+9+%29+\"
\n" ); document.write( "(2) \"+t+-+9+=+3+\"
\n" ); document.write( "(2) \"+t+=+12+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );