document.write( "Question 1150212: Thirty percent of students at a large university are known to be short-sighted. If twenty
\n" );
document.write( "Students are picked at random, find the probability that at most two of them are shortsighted. \n" );
document.write( "
Algebra.Com's Answer #771632 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! binomial with n=30 and p=0.3 \n" ); document.write( "probability 0 are short sighted is 0.7^30 \n" ); document.write( "probability 1 is short sighted is 30*0.7^29*0.3, The 30 being the number of different ways \n" ); document.write( "probability of 2 is 30C2*0.7^28*0.3^2 \n" ); document.write( "first is 0.00002 \n" ); document.write( "second is 0.0003 \n" ); document.write( "third is 0.0018 \n" ); document.write( "the probability is 0.0021. Table shows the same.\r \n" ); document.write( "\n" ); document.write( "expected value is 6 \n" ); document.write( "variance is 4.2 sd is 2.05 \n" ); document.write( " |