document.write( "Question 1150200: There are 7 women and 5 men in a department. Four people are needed for a committee.
\n" ); document.write( "a) In how many ways can a committee of 4 people be selected?
\n" ); document.write( "b) In how many ways can this committee be selected if there must be exactly 2 men and 2 women on the committee?
\n" ); document.write( "c) In how many ways can this committee be selected if there must be at least 2 women on the committee?
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Algebra.Com's Answer #771626 by VFBundy(438)\"\" \"About 
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a) In how many ways can a committee of 4 people be selected?
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\n" ); document.write( "12C4 = \"12%21%2F%284%21%2A8%21%29\" = 495
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\n" ); document.write( "b) In how many ways can this committee be selected if there must be exactly 2 men and 2 women on the committee?
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\n" ); document.write( "7C2 * 5C2 = \"%287%21%2F%282%21%2A5%21%29%29%2A%285%21%2F%282%21%2A3%21%29%29\" = 210
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\n" ); document.write( "c) In how many ways can this committee be selected if there must be at least 2 women on the committee?
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\n" ); document.write( "Ways to choose 4 women and 0 men: 7C4 = \"%287%21%2F%284%21%2A3%21%29%29\" = 35
\n" ); document.write( "Ways to choose 3 women and 1 man: 7C3 * 5C1 = \"%287%21%2F%283%21%2A4%21%29%29%2A%285%21%2F%281%21%2A4%21%29%29\" = 175
\n" ); document.write( "Ways to choose 2 women and 2 men: 7C2 * 5C2 = \"%287%21%2F%282%21%2A5%21%29%29%2A%285%21%2F%282%21%2A3%21%29%29\" = 210
\n" ); document.write( "35 + 175 + 210 = 420
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