document.write( "Question 1150085: Given: ∆AKM, R = 2,
\n" ); document.write( " m∠A = 33°, O∈AM.
\n" ); document.write( " Find: perimeter of ∆AKM\r
\n" ); document.write( "\n" ); document.write( "https://lh3.googleusercontent.com/XxKrlU8bFG1SlkyIN7TnUgujgwFyLSlOVvHPOX7Z5ROrqCGAlXuvwvfMN9C3S4fiiK7Zbg=s97
\n" ); document.write( "

Algebra.Com's Answer #771585 by Edwin McCravy(20067)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( " \r\n" );
document.write( "\r\n" );
document.write( "∆AKM is a right triangle for it is inscribed in semicircle O.\r\n" );
document.write( "\r\n" );
document.write( "AM = diameter of semi-circle O = 2R = 2(2) = 4\r\n" );
document.write( "\r\n" );
document.write( "\"%22AK%22%2F%22AM%22=cos%2833%5Eo%29\"\r\n" );
document.write( "\"AK+=+AM%2Acos%2833%5Eo%29\"\r\n" );
document.write( "\"AK+=+4cos%2833%5Eo%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%22KM%22%2F%22AM%22=sin%2833%5Eo%29\"\r\n" );
document.write( "\"KM+=+AM%2Asin%2833%5Eo%29\"\r\n" );
document.write( "\"KM+=+4sin%2833%5Eo%29\"\r\n" );
document.write( "\r\n" );
document.write( "The perimeter of a triangle is the sum of the three sides.\r\n" );
document.write( "\r\n" );
document.write( "\"perimeter=AK%2BKM%2BAM\"\r\n" );
document.write( "\r\n" );
document.write( "\"perimeter=4cos%2833%5Eo%29%2B4sin%2833%5Eo%29%2B4\"\r\n" );
document.write( "\r\n" );
document.write( "Approximately 9.533238412\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "
\n" ); document.write( "
\n" );